Integrand size = 22, antiderivative size = 75 \[ \int \frac {(1-2 x)^3}{(2+3 x)^6 (3+5 x)^2} \, dx=-\frac {343}{45 (2+3 x)^5}-\frac {784}{9 (2+3 x)^4}-\frac {847}{(2+3 x)^3}-\frac {8349}{(2+3 x)^2}-\frac {103455}{2+3 x}-\frac {33275}{3+5 x}+617100 \log (2+3 x)-617100 \log (3+5 x) \]
-343/45/(2+3*x)^5-784/9/(2+3*x)^4-847/(2+3*x)^3-8349/(2+3*x)^2-103455/(2+3 *x)-33275/(3+5*x)+617100*ln(2+3*x)-617100*ln(3+5*x)
Time = 0.04 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.83 \[ \int \frac {(1-2 x)^3}{(2+3 x)^6 (3+5 x)^2} \, dx=-\frac {280877649+2130399775 x+6461351715 x^2+9795413430 x^3+7422787350 x^4+2249329500 x^5}{45 (2+3 x)^5 (3+5 x)}+617100 \log (5 (2+3 x))-617100 \log (3+5 x) \]
-1/45*(280877649 + 2130399775*x + 6461351715*x^2 + 9795413430*x^3 + 742278 7350*x^4 + 2249329500*x^5)/((2 + 3*x)^5*(3 + 5*x)) + 617100*Log[5*(2 + 3*x )] - 617100*Log[3 + 5*x]
Time = 0.21 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {99, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {(1-2 x)^3}{(3 x+2)^6 (5 x+3)^2} \, dx\) |
\(\Big \downarrow \) 99 |
\(\displaystyle \int \left (-\frac {3085500}{5 x+3}+\frac {166375}{(5 x+3)^2}+\frac {1851300}{3 x+2}+\frac {310365}{(3 x+2)^2}+\frac {50094}{(3 x+2)^3}+\frac {7623}{(3 x+2)^4}+\frac {3136}{3 (3 x+2)^5}+\frac {343}{3 (3 x+2)^6}\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle -\frac {103455}{3 x+2}-\frac {33275}{5 x+3}-\frac {8349}{(3 x+2)^2}-\frac {847}{(3 x+2)^3}-\frac {784}{9 (3 x+2)^4}-\frac {343}{45 (3 x+2)^5}+617100 \log (3 x+2)-617100 \log (5 x+3)\) |
-343/(45*(2 + 3*x)^5) - 784/(9*(2 + 3*x)^4) - 847/(2 + 3*x)^3 - 8349/(2 + 3*x)^2 - 103455/(2 + 3*x) - 33275/(3 + 5*x) + 617100*Log[2 + 3*x] - 617100 *Log[3 + 5*x]
3.15.15.3.1 Defintions of rubi rules used
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] && (IntegerQ[p] | | (GtQ[m, 0] && GeQ[n, -1]))
Time = 2.45 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.77
method | result | size |
norman | \(\frac {-217675854 x^{3}-164950830 x^{4}-49985100 x^{5}-\frac {430756781}{3} x^{2}-\frac {426079955}{9} x -\frac {93625883}{15}}{\left (2+3 x \right )^{5} \left (3+5 x \right )}+617100 \ln \left (2+3 x \right )-617100 \ln \left (3+5 x \right )\) | \(58\) |
risch | \(\frac {-217675854 x^{3}-164950830 x^{4}-49985100 x^{5}-\frac {430756781}{3} x^{2}-\frac {426079955}{9} x -\frac {93625883}{15}}{\left (2+3 x \right )^{5} \left (3+5 x \right )}+617100 \ln \left (2+3 x \right )-617100 \ln \left (3+5 x \right )\) | \(59\) |
default | \(-\frac {343}{45 \left (2+3 x \right )^{5}}-\frac {784}{9 \left (2+3 x \right )^{4}}-\frac {847}{\left (2+3 x \right )^{3}}-\frac {8349}{\left (2+3 x \right )^{2}}-\frac {103455}{2+3 x}-\frac {33275}{3+5 x}+617100 \ln \left (2+3 x \right )-617100 \ln \left (3+5 x \right )\) | \(72\) |
parallelrisch | \(\frac {4739328080 x -995258880000 \ln \left (x +\frac {3}{5}\right ) x^{2}+2026062720000 \ln \left (\frac {2}{3}+x \right ) x^{3}-260663040000 \ln \left (x +\frac {3}{5}\right ) x +995258880000 \ln \left (\frac {2}{3}+x \right ) x^{2}+260663040000 \ln \left (\frac {2}{3}+x \right ) x +125153183619 x^{5}+37918482615 x^{6}+108982603320 x^{3}+165187156230 x^{4}+35939904000 x^{2}+2319308640000 \ln \left (\frac {2}{3}+x \right ) x^{4}+28435968000 \ln \left (\frac {2}{3}+x \right )-28435968000 \ln \left (x +\frac {3}{5}\right )+1415578032000 \ln \left (\frac {2}{3}+x \right ) x^{5}-2026062720000 \ln \left (x +\frac {3}{5}\right ) x^{3}-1415578032000 \ln \left (x +\frac {3}{5}\right ) x^{5}-2319308640000 \ln \left (x +\frac {3}{5}\right ) x^{4}+359892720000 \ln \left (\frac {2}{3}+x \right ) x^{6}-359892720000 \ln \left (x +\frac {3}{5}\right ) x^{6}}{480 \left (2+3 x \right )^{5} \left (3+5 x \right )}\) | \(162\) |
(-217675854*x^3-164950830*x^4-49985100*x^5-430756781/3*x^2-426079955/9*x-9 3625883/15)/(2+3*x)^5/(3+5*x)+617100*ln(2+3*x)-617100*ln(3+5*x)
Time = 0.22 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.80 \[ \int \frac {(1-2 x)^3}{(2+3 x)^6 (3+5 x)^2} \, dx=-\frac {2249329500 \, x^{5} + 7422787350 \, x^{4} + 9795413430 \, x^{3} + 6461351715 \, x^{2} + 27769500 \, {\left (1215 \, x^{6} + 4779 \, x^{5} + 7830 \, x^{4} + 6840 \, x^{3} + 3360 \, x^{2} + 880 \, x + 96\right )} \log \left (5 \, x + 3\right ) - 27769500 \, {\left (1215 \, x^{6} + 4779 \, x^{5} + 7830 \, x^{4} + 6840 \, x^{3} + 3360 \, x^{2} + 880 \, x + 96\right )} \log \left (3 \, x + 2\right ) + 2130399775 \, x + 280877649}{45 \, {\left (1215 \, x^{6} + 4779 \, x^{5} + 7830 \, x^{4} + 6840 \, x^{3} + 3360 \, x^{2} + 880 \, x + 96\right )}} \]
-1/45*(2249329500*x^5 + 7422787350*x^4 + 9795413430*x^3 + 6461351715*x^2 + 27769500*(1215*x^6 + 4779*x^5 + 7830*x^4 + 6840*x^3 + 3360*x^2 + 880*x + 96)*log(5*x + 3) - 27769500*(1215*x^6 + 4779*x^5 + 7830*x^4 + 6840*x^3 + 3 360*x^2 + 880*x + 96)*log(3*x + 2) + 2130399775*x + 280877649)/(1215*x^6 + 4779*x^5 + 7830*x^4 + 6840*x^3 + 3360*x^2 + 880*x + 96)
Time = 0.09 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.95 \[ \int \frac {(1-2 x)^3}{(2+3 x)^6 (3+5 x)^2} \, dx=- \frac {2249329500 x^{5} + 7422787350 x^{4} + 9795413430 x^{3} + 6461351715 x^{2} + 2130399775 x + 280877649}{54675 x^{6} + 215055 x^{5} + 352350 x^{4} + 307800 x^{3} + 151200 x^{2} + 39600 x + 4320} - 617100 \log {\left (x + \frac {3}{5} \right )} + 617100 \log {\left (x + \frac {2}{3} \right )} \]
-(2249329500*x**5 + 7422787350*x**4 + 9795413430*x**3 + 6461351715*x**2 + 2130399775*x + 280877649)/(54675*x**6 + 215055*x**5 + 352350*x**4 + 307800 *x**3 + 151200*x**2 + 39600*x + 4320) - 617100*log(x + 3/5) + 617100*log(x + 2/3)
Time = 0.22 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.01 \[ \int \frac {(1-2 x)^3}{(2+3 x)^6 (3+5 x)^2} \, dx=-\frac {2249329500 \, x^{5} + 7422787350 \, x^{4} + 9795413430 \, x^{3} + 6461351715 \, x^{2} + 2130399775 \, x + 280877649}{45 \, {\left (1215 \, x^{6} + 4779 \, x^{5} + 7830 \, x^{4} + 6840 \, x^{3} + 3360 \, x^{2} + 880 \, x + 96\right )}} - 617100 \, \log \left (5 \, x + 3\right ) + 617100 \, \log \left (3 \, x + 2\right ) \]
-1/45*(2249329500*x^5 + 7422787350*x^4 + 9795413430*x^3 + 6461351715*x^2 + 2130399775*x + 280877649)/(1215*x^6 + 4779*x^5 + 7830*x^4 + 6840*x^3 + 33 60*x^2 + 880*x + 96) - 617100*log(5*x + 3) + 617100*log(3*x + 2)
Time = 0.29 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.01 \[ \int \frac {(1-2 x)^3}{(2+3 x)^6 (3+5 x)^2} \, dx=-\frac {33275}{5 \, x + 3} + \frac {25 \, {\left (\frac {13068279}{5 \, x + 3} + \frac {7369449}{{\left (5 \, x + 3\right )}^{2}} + \frac {1895648}{{\left (5 \, x + 3\right )}^{3}} + \frac {190707}{{\left (5 \, x + 3\right )}^{4}} + 8846550\right )}}{{\left (\frac {1}{5 \, x + 3} + 3\right )}^{5}} + 617100 \, \log \left ({\left | -\frac {1}{5 \, x + 3} - 3 \right |}\right ) \]
-33275/(5*x + 3) + 25*(13068279/(5*x + 3) + 7369449/(5*x + 3)^2 + 1895648/ (5*x + 3)^3 + 190707/(5*x + 3)^4 + 8846550)/(1/(5*x + 3) + 3)^5 + 617100*l og(abs(-1/(5*x + 3) - 3))
Time = 0.05 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.88 \[ \int \frac {(1-2 x)^3}{(2+3 x)^6 (3+5 x)^2} \, dx=1234200\,\mathrm {atanh}\left (30\,x+19\right )-\frac {41140\,x^5+135762\,x^4+\frac {24186206\,x^3}{135}+\frac {430756781\,x^2}{3645}+\frac {85215991\,x}{2187}+\frac {93625883}{18225}}{x^6+\frac {59\,x^5}{15}+\frac {58\,x^4}{9}+\frac {152\,x^3}{27}+\frac {224\,x^2}{81}+\frac {176\,x}{243}+\frac {32}{405}} \]